The problem asks to find the slope of line segment $TQ$ and the slope of line segment $SR$ given the vertices of quadrilateral $QRST$: $Q(3, 2)$, $R(1, -6)$, $S(-1, -6)$, and $T(-3, 2)$.

GeometryCoordinate GeometrySlopeLine SegmentsQuadrilaterals
2025/3/13

1. Problem Description

The problem asks to find the slope of line segment TQTQ and the slope of line segment SRSR given the vertices of quadrilateral QRSTQRST: Q(3,2)Q(3, 2), R(1,6)R(1, -6), S(1,6)S(-1, -6), and T(3,2)T(-3, 2).

2. Solution Steps

To find the slope of a line segment, we use the formula:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
For the slope of TQTQ, we have T(3,2)T(-3, 2) and Q(3,2)Q(3, 2).
mTQ=223(3)=06=0m_{TQ} = \frac{2 - 2}{3 - (-3)} = \frac{0}{6} = 0
For the slope of SRSR, we have S(1,6)S(-1, -6) and R(1,6)R(1, -6).
mSR=6(6)1(1)=02=0m_{SR} = \frac{-6 - (-6)}{1 - (-1)} = \frac{0}{2} = 0

3. Final Answer

Slope of TQTQ: 0
Slope of SRSR: 0

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