The problem is to find the value of $P$ in the given diagram where two lines intersect.

GeometryAnglesLinear PairGeometry
2025/5/22

1. Problem Description

The problem is to find the value of PP in the given diagram where two lines intersect.

2. Solution Steps

The sum of angles on one side of a straight line is 180180^{\circ}.
The angles 6060^{\circ}, PP and 1010^{\circ} lie on one side of a straight line. Therefore, their sum must be equal to 180180^{\circ}.
60+P+10=18060 + P + 10 = 180
P+70=180P + 70 = 180
P=18070P = 180 - 70
P=110P = 110

3. Final Answer

The value of PP is 110110^{\circ}.

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