We are asked to find the length of an arc intercepted by a central angle $\theta$ in a circle of radius $r$. We are given $r = 49.97$ ft and $\theta = \frac{\pi}{5}$ radians. We need to round the answer to 1 decimal place.

GeometryArc LengthCirclesRadiansTrigonometry
2025/3/13

1. Problem Description

We are asked to find the length of an arc intercepted by a central angle θ\theta in a circle of radius rr. We are given r=49.97r = 49.97 ft and θ=π5\theta = \frac{\pi}{5} radians. We need to round the answer to 1 decimal place.

2. Solution Steps

The formula for the arc length ss is given by:
s=rθs = r\theta
where rr is the radius and θ\theta is the central angle in radians.
Given r=49.97r = 49.97 ft and θ=π5\theta = \frac{\pi}{5} radians, we can substitute these values into the formula:
s=49.97π5s = 49.97 \cdot \frac{\pi}{5}
Using the value π3.14159\pi \approx 3.14159, we get:
s=49.973.14159549.970.62831831.39995s = 49.97 \cdot \frac{3.14159}{5} \approx 49.97 \cdot 0.628318 \approx 31.39995
Rounding to 1 decimal place, we get s31.4s \approx 31.4 ft.

3. Final Answer

31.4 ft

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