The problem is to fill in the blanks in the given flowchart to create a program that counts the number of even numbers entered by the user. The program initializes a counter `count` to $A$ and `evenCount` to 0. It iterates as long as `count` is less than or equal to $B$. In each iteration, the user enters a number $n$. If $n$ is even, `evenCount` is incremented. The value of `count` is updated in each iteration. Finally, the program displays the value of `evenCount`.
2025/4/13
1. Problem Description
The problem is to fill in the blanks in the given flowchart to create a program that counts the number of even numbers entered by the user. The program initializes a counter `count` to and `evenCount` to
0. It iterates as long as `count` is less than or equal to $B$. In each iteration, the user enters a number $n$. If $n$ is even, `evenCount` is incremented. The value of `count` is updated in each iteration. Finally, the program displays the value of `evenCount`.
2. Solution Steps
Let's analyze the flowchart step by step.
* The program starts by initializing `count = A` and `evenCount = 0`.
* The program enters a loop that continues as long as `count <= B`.
* Inside the loop, the user inputs a number .
* The program checks if has a remainder of 0, which is equivalent to checking if is even.
* If is even, `evenCount` needs to be incremented.
* After processing the number, `count` needs to be incremented to proceed to the next number.
Based on this analysis, we can fill in the blanks:
* A: We can choose to start at
1. So $A = 1$.
* B: Let's assume we want to read 10 numbers. So .
* C: The path from "Balance of n/2 = 0?" to the box E happens if "Balance of n/2 = 0?" is true, that is, if the input number is even.
* E: This box contains the increment of the `evenCount` variable. So `evenCount = evenCount + 1` or `evenCount++`.
* D: This path happens if "Balance of n/2 = 0?" is false, that is, if the input number is odd.
* F: In each iteration, we need to increment the value of the `count` variable. Thus, `count = count + 1` or `count++`.
* I: The arrow label is "yes," indicating the direction to follow when the input number is even.
3. Final Answer
A = 1
B = 10
C = yes
E = evenCount = evenCount + 1
D = no
F = count = count + 1
I = yes