The problem asks to find the approximate volume of the trashcan. The trashcan is composed of a rectangular prism and a triangular prism. The dimensions of the rectangular prism are 26 inches, 18 inches, and 22 inches. The dimensions of the triangular prism are: the height is 18 inches, the base of the triangle is 26 inches, and the length of the prism is 18 inches.

1. Problem Description

The problem asks to find the approximate volume of the trashcan. The trashcan is composed of a rectangular prism and a triangular prism. The dimensions of the rectangular prism are 26 inches, 18 inches, and 22 inches. The dimensions of the triangular prism are: the height is 18 inches, the base of the triangle is 26 inches, and the length of the prism is 18 inches.

2. Solution Steps

First, calculate the volume of the rectangular prism.

$V_{rectangular} = length \times width \times height$

$V_{rectangular} = 26 \times 18 \times 22$

$V_{rectangular} = 10296$ cubic inches

Second, calculate the volume of the triangular prism.

$V_{triangular} = area_{triangle} \times length$

$area_{triangle} = \frac{1}{2} \times base \times height$

$area_{triangle} = \frac{1}{2} \times 26 \times 18$

$area_{triangle} = 234$ square inches

$V_{triangular} = 234 \times 18$

$V_{triangular} = 4212$ cubic inches

Third, calculate the total volume of the trashcan.

$V_{total} = V_{rectangular} + V_{triangular}$

$V_{total} = 10296 + 4212$

$V_{total} = 14508$ cubic inches

3. Final Answer

14508 $in^3$