We are given four sets: $A = \{0, 2, 4, 6, 8, 10\}$ $B = \{1, 3, 5, 7, 9\}$ $C = \{1, 2, 4, 5, 7, 8\}$ $D = \{1, 2, 3, 5, 7, 8, 9\}$ We need to find the following sets: (a) $(A - B) - C$ (b) $(A \cap B) \cup (A \cap C)$ (c) $D \cap (A \cap C)$ (e) $(A \cup B) - (C \cap D)$

Discrete MathematicsSet TheorySet OperationsUnionIntersectionSet Difference
2025/4/15

1. Problem Description

We are given four sets:
A={0,2,4,6,8,10}A = \{0, 2, 4, 6, 8, 10\}
B={1,3,5,7,9}B = \{1, 3, 5, 7, 9\}
C={1,2,4,5,7,8}C = \{1, 2, 4, 5, 7, 8\}
D={1,2,3,5,7,8,9}D = \{1, 2, 3, 5, 7, 8, 9\}
We need to find the following sets:
(a) (AB)C(A - B) - C
(b) (AB)(AC)(A \cap B) \cup (A \cap C)
(c) D(AC)D \cap (A \cap C)
(e) (AB)(CD)(A \cup B) - (C \cap D)

2. Solution Steps

(a) (AB)C(A - B) - C
First, we find ABA - B, which is the set of elements in AA but not in BB.
AB={0,2,4,6,8,10}A - B = \{0, 2, 4, 6, 8, 10\}
Then we find (AB)C(A - B) - C, which is the set of elements in ABA - B but not in CC.
(AB)C={0,2,4,6,8,10}{1,2,4,5,7,8}={0,6,10}(A - B) - C = \{0, 2, 4, 6, 8, 10\} - \{1, 2, 4, 5, 7, 8\} = \{0, 6, 10\}
(b) (AB)(AC)(A \cap B) \cup (A \cap C)
First, we find ABA \cap B, which is the set of elements in both AA and BB.
AB={0,2,4,6,8,10}{1,3,5,7,9}=A \cap B = \{0, 2, 4, 6, 8, 10\} \cap \{1, 3, 5, 7, 9\} = \emptyset
Then, we find ACA \cap C, which is the set of elements in both AA and CC.
AC={0,2,4,6,8,10}{1,2,4,5,7,8}={2,4,8}A \cap C = \{0, 2, 4, 6, 8, 10\} \cap \{1, 2, 4, 5, 7, 8\} = \{2, 4, 8\}
Finally, we find (AB)(AC)(A \cap B) \cup (A \cap C), which is the union of the two sets.
(AB)(AC)={2,4,8}={2,4,8}(A \cap B) \cup (A \cap C) = \emptyset \cup \{2, 4, 8\} = \{2, 4, 8\}
(c) D(AC)D \cap (A \cap C)
We already found AC={2,4,8}A \cap C = \{2, 4, 8\}.
Now, we find D(AC)D \cap (A \cap C), which is the set of elements in both DD and ACA \cap C.
D(AC)={1,2,3,5,7,8,9}{2,4,8}={2,8}D \cap (A \cap C) = \{1, 2, 3, 5, 7, 8, 9\} \cap \{2, 4, 8\} = \{2, 8\}
(e) (AB)(CD)(A \cup B) - (C \cap D)
First, we find ABA \cup B, which is the set of elements in either AA or BB or both.
AB={0,2,4,6,8,10}{1,3,5,7,9}={0,1,2,3,4,5,6,7,8,9,10}A \cup B = \{0, 2, 4, 6, 8, 10\} \cup \{1, 3, 5, 7, 9\} = \{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}
Then, we find CDC \cap D, which is the set of elements in both CC and DD.
CD={1,2,4,5,7,8}{1,2,3,5,7,8,9}={1,2,5,7,8}C \cap D = \{1, 2, 4, 5, 7, 8\} \cap \{1, 2, 3, 5, 7, 8, 9\} = \{1, 2, 5, 7, 8\}
Finally, we find (AB)(CD)(A \cup B) - (C \cap D), which is the set of elements in ABA \cup B but not in CDC \cap D.
(AB)(CD)={0,1,2,3,4,5,6,7,8,9,10}{1,2,5,7,8}={0,3,4,6,9,10}(A \cup B) - (C \cap D) = \{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10\} - \{1, 2, 5, 7, 8\} = \{0, 3, 4, 6, 9, 10\}

3. Final Answer

(a) {0,6,10}\{0, 6, 10\}
(b) {2,4,8}\{2, 4, 8\}
(c) {2,8}\{2, 8\}
(e) {0,3,4,6,9,10}\{0, 3, 4, 6, 9, 10\}

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