Given sets $A = \{0, 2, 4, 6, 8, 10\}$, $B = \{1, 3, 5, 7, 9\}$, $C = \{1, 2, 4, 5, 7, 8\}$, and $D = \{1, 2, 3, 5, 7, 8, 9\}$, we are asked to find the following sets: (a) $(A - B) - C$ (b) $(A \cap B) \cup (A \cap C)$ (c) $D \cap (A \cap C)$ (e) $(A \cup B) - (C \cap D)$

Discrete MathematicsSet TheorySet OperationsUnionIntersectionSet Difference
2025/4/15

1. Problem Description

Given sets A={0,2,4,6,8,10}A = \{0, 2, 4, 6, 8, 10\}, B={1,3,5,7,9}B = \{1, 3, 5, 7, 9\}, C={1,2,4,5,7,8}C = \{1, 2, 4, 5, 7, 8\}, and D={1,2,3,5,7,8,9}D = \{1, 2, 3, 5, 7, 8, 9\}, we are asked to find the following sets:
(a) (AB)C(A - B) - C
(b) (AB)(AC)(A \cap B) \cup (A \cap C)
(c) D(AC)D \cap (A \cap C)
(e) (AB)(CD)(A \cup B) - (C \cap D)

2. Solution Steps

(a) (AB)C(A - B) - C
ABA - B is the set of elements in AA that are not in BB. Since AA contains only even numbers and BB contains only odd numbers, AB=A={0,2,4,6,8,10}A - B = A = \{0, 2, 4, 6, 8, 10\}.
(AB)C=AC(A - B) - C = A - C is the set of elements in AA that are not in CC.
AC={0,2,4,6,8,10}{1,2,4,5,7,8}={0,6,10}A - C = \{0, 2, 4, 6, 8, 10\} - \{1, 2, 4, 5, 7, 8\} = \{0, 6, 10\}
(b) (AB)(AC)(A \cap B) \cup (A \cap C)
ABA \cap B is the set of elements that are in both AA and BB. Since AA contains only even numbers and BB contains only odd numbers, AB=A \cap B = \emptyset.
ACA \cap C is the set of elements that are in both AA and CC.
AC={0,2,4,6,8,10}{1,2,4,5,7,8}={2,4,8}A \cap C = \{0, 2, 4, 6, 8, 10\} \cap \{1, 2, 4, 5, 7, 8\} = \{2, 4, 8\}.
(AB)(AC)={2,4,8}={2,4,8}(A \cap B) \cup (A \cap C) = \emptyset \cup \{2, 4, 8\} = \{2, 4, 8\}.
(c) D(AC)D \cap (A \cap C)
We already found that AC={2,4,8}A \cap C = \{2, 4, 8\}.
D(AC)=D{2,4,8}={1,2,3,5,7,8,9}{2,4,8}={2,8}D \cap (A \cap C) = D \cap \{2, 4, 8\} = \{1, 2, 3, 5, 7, 8, 9\} \cap \{2, 4, 8\} = \{2, 8\}.
(e) (AB)(CD)(A \cup B) - (C \cap D)
ABA \cup B is the set of elements that are in AA or BB or both.
AB={0,2,4,6,8,10}{1,3,5,7,9}={0,1,2,3,4,5,6,7,8,9,10}A \cup B = \{0, 2, 4, 6, 8, 10\} \cup \{1, 3, 5, 7, 9\} = \{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}.
CDC \cap D is the set of elements that are in both CC and DD.
CD={1,2,4,5,7,8}{1,2,3,5,7,8,9}={1,2,5,7,8}C \cap D = \{1, 2, 4, 5, 7, 8\} \cap \{1, 2, 3, 5, 7, 8, 9\} = \{1, 2, 5, 7, 8\}.
(AB)(CD)={0,1,2,3,4,5,6,7,8,9,10}{1,2,5,7,8}={0,3,4,6,9,10}(A \cup B) - (C \cap D) = \{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10\} - \{1, 2, 5, 7, 8\} = \{0, 3, 4, 6, 9, 10\}.

3. Final Answer

(a) {0,6,10}\{0, 6, 10\}
(b) {2,4,8}\{2, 4, 8\}
(c) {2,8}\{2, 8\}
(e) {0,3,4,6,9,10}\{0, 3, 4, 6, 9, 10\}

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