A car travels at a constant speed. Two photos of the car were taken $0.5$ seconds apart. The distance between two adjacent lines on the road is $1.7$ m. We need to calculate the speed of the car in m/s, rounded to 1 decimal place.

Applied MathematicsSpeedDistanceTimeUnits ConversionPhysics
2025/3/14

1. Problem Description

A car travels at a constant speed. Two photos of the car were taken 0.50.5 seconds apart. The distance between two adjacent lines on the road is 1.71.7 m. We need to calculate the speed of the car in m/s, rounded to 1 decimal place.

2. Solution Steps

First, we need to determine the number of lines the car has moved past between the two photos. From the given pictures, the car has moved past 3 lines.
The distance traveled is therefore 3 times the distance between each line.
Distance = number of lines * distance per line
Distance =3×1.7= 3 \times 1.7 m =5.1= 5.1 m.
The time taken is 0.50.5 s.
The formula for speed is:
Speed=DistanceTimeSpeed = \frac{Distance}{Time}
Substitute the values:
Speed=5.10.5=10.2Speed = \frac{5.1}{0.5} = 10.2 m/s

3. Final Answer

The speed of the car is 10.2 m/s.

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