The problem asks to find the volume of a rectangular pyramid. The given dimensions are: length = $9$ yd, width = $8$ yd, and height = $5$ yd. We need to find the volume and include the correct unit in the answer.

1. Problem Description

The problem asks to find the volume of a rectangular pyramid. The given dimensions are: length = $9$ yd, width = $8$ yd, and height = $5$ yd. We need to find the volume and include the correct unit in the answer.

2. Solution Steps

The formula for the volume of a pyramid is:

$V = \frac{1}{3}Bh$

where $V$ is the volume, $B$ is the area of the base, and $h$ is the height of the pyramid.

Since the base is a rectangle, the area of the base is:

$B = lw$

where $l$ is the length and $w$ is the width.

In this case, $l = 9$ yd and $w = 8$ yd. So, the area of the base is:

$B = (9 \text{ yd})(8 \text{ yd}) = 72 \text{ yd}^2$

The height of the pyramid is given as $h = 5$ yd. Now, we can calculate the volume of the pyramid:

$V = \frac{1}{3}Bh = \frac{1}{3}(72 \text{ yd}^2)(5 \text{ yd}) = \frac{1}{3}(360 \text{ yd}^3) = 120 \text{ yd}^3$

3. Final Answer

The volume of the rectangular pyramid is $120 \text{ yd}^3$.