The problem asks us to find the volume of a sand pile. The sand pile has a circular base. The diameter of the base is 12 ft and the height of the sand pile is 16 ft. We need to round the answer to the nearest whole unit.

GeometryVolumeConeRadiusHeightApproximation
2025/4/16

1. Problem Description

The problem asks us to find the volume of a sand pile. The sand pile has a circular base. The diameter of the base is 12 ft and the height of the sand pile is 16 ft. We need to round the answer to the nearest whole unit.

2. Solution Steps

The sand pile can be modeled as a cone.
The volume of a cone is given by the formula:
V=13πr2hV = \frac{1}{3} \pi r^2 h
where VV is the volume, rr is the radius, and hh is the height.
We are given that the diameter is 12 ft, so the radius is r=122=6r = \frac{12}{2} = 6 ft.
We are given that the height is h=16h = 16 ft.
Substituting these values into the formula for the volume of a cone, we get:
V=13π(62)(16)V = \frac{1}{3} \pi (6^2) (16)
V=13π(36)(16)V = \frac{1}{3} \pi (36) (16)
V=13π(576)V = \frac{1}{3} \pi (576)
V=192πV = 192 \pi
Using the π\pi button on the calculator, π3.14159\pi \approx 3.14159
V192(3.14159)603.185V \approx 192(3.14159) \approx 603.185
We need to round the answer to the nearest whole unit.
V603V \approx 603

3. Final Answer

603

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