The problem asks whether the equation $y = \sqrt{8x}$ represents a proportional relationship.

AlgebraProportional RelationshipsSquare RootsFunctions
2025/4/16

1. Problem Description

The problem asks whether the equation y=8xy = \sqrt{8x} represents a proportional relationship.

2. Solution Steps

A proportional relationship can be expressed in the form y=kxy = kx, where kk is the constant of proportionality. The given equation is y=8xy = \sqrt{8x}. This can be written as y=8xy = \sqrt{8} \sqrt{x}.
Let's analyze if the equation can be written in the form y=kxy = kx.
If we square both sides of the given equation, we get y2=8xy^2 = 8x. This can be written as x=18y2x = \frac{1}{8} y^2. Since the power of xx is 1 and yy is 2, this is not in the form y=kxy = kx.
Alternatively, we have y=8xy = \sqrt{8} \sqrt{x}. In order for yy to be proportional to xx, we must have a relationship of the form y=kxy=kx. Here, yy is proportional to x\sqrt{x} instead of xx. So it is not a proportional relationship.

3. Final Answer

Non-Proportional

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