Car A and Car B are traveling at constant speeds. The problem asks to determine which car is traveling at a greater speed and how we know. We are given a graph representing the distance traveled by Car A over time, and a table with the distance traveled by Car B over time.

Applied MathematicsSpeedDistanceTimeRateGraph AnalysisTable AnalysisWord Problem
2025/4/21

1. Problem Description

Car A and Car B are traveling at constant speeds. The problem asks to determine which car is traveling at a greater speed and how we know. We are given a graph representing the distance traveled by Car A over time, and a table with the distance traveled by Car B over time.

2. Solution Steps

To determine which car is traveling at a greater speed, we need to calculate the speed of each car. Speed is calculated as distance divided by time:
Speed=DistanceTimeSpeed = \frac{Distance}{Time}
For Car A, we can pick a point from the graph. For example, at 12 minutes, the distance is 8 miles. Therefore, the speed of Car A is:
SpeedA=8 miles12 minutes=23 miles/minute0.667 miles/minuteSpeed_A = \frac{8 \text{ miles}}{12 \text{ minutes}} = \frac{2}{3} \text{ miles/minute} \approx 0.667 \text{ miles/minute}
For Car B, we can use any of the data points from the table. Let's use the first data point (15 minutes, 12.5 miles):
SpeedB=12.5 miles15 minutes=12.515 miles/minute=2530 miles/minute=56 miles/minute0.833 miles/minuteSpeed_B = \frac{12.5 \text{ miles}}{15 \text{ minutes}} = \frac{12.5}{15} \text{ miles/minute} = \frac{25}{30} \text{ miles/minute} = \frac{5}{6} \text{ miles/minute} \approx 0.833 \text{ miles/minute}
Now, we compare the speeds:
SpeedA0.667 miles/minuteSpeed_A \approx 0.667 \text{ miles/minute}
SpeedB0.833 miles/minuteSpeed_B \approx 0.833 \text{ miles/minute}
Since 0.833>0.6670.833 > 0.667, Car B is traveling at a greater speed.

3. Final Answer

Car B is traveling at a greater speed. We know this because the calculated speed for Car B (5/65/6 miles/minute) is greater than the calculated speed for Car A (2/32/3 miles/minute).

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