The problem requires us to draw a triangle using a ruler and protractor, given one side (7 cm) and two angles (40° and 20°). We then need to measure the length of the side labeled $x$ to 1 decimal place. Because the problem explicitly asks for a drawing and measurement, I cannot provide a definitive numerical answer, but I can give the correct methodology and expected answer.

1. Problem Description

The problem requires us to draw a triangle using a ruler and protractor, given one side (7 cm) and two angles (40° and 20°). We then need to measure the length of the side labeled $x$ to 1 decimal place. Because the problem explicitly asks for a drawing and measurement, I cannot provide a definitive numerical answer, but I can give the correct methodology and expected answer.

2. Solution Steps

Step 1: Calculate the third angle of the triangle.

The sum of angles in a triangle is 180°. Let the third angle be $A$.

$A + 40° + 20° = 180°$

$A = 180° - 40° - 20° = 120°$

Step 2: Draw the triangle accurately.

- Draw a horizontal line of 7 cm.

- At one end of the line, construct an angle of 40° using a protractor.

- At the other end of the line, construct an angle of 20° using a protractor.

- Extend the lines from the angles until they intersect, forming the third vertex of the triangle.

Step 3: Measure the length of the side labeled $x$.

- Using a ruler, measure the length of the side opposite the 40° angle. This is the length $x$.

- Record the length to 1 decimal place.

Step 4: Estimate using Sine Rule

$\frac{x}{\sin(40)} = \frac{7}{\sin(120)}$

$x = \frac{7 \sin(40)}{\sin(120)}$

$x = \frac{7 \times 0.6428}{0.8660}$

$x \approx 5.2$ cm

3. Final Answer

The length of side $x$ is approximately 5.2 cm. The exact value you obtain after drawing and measuring may vary slightly depending on the accuracy of your drawing and measurement. You should write down the measured value to one decimal place.