Solve the equation $\frac{2x}{3} = \frac{3}{7}$ for $x$.

AlgebraLinear EquationsSolving EquationsFractions
2025/3/16

1. Problem Description

Solve the equation 2x3=37\frac{2x}{3} = \frac{3}{7} for xx.

2. Solution Steps

The given equation is:
2x3=37\frac{2x}{3} = \frac{3}{7}
To solve for xx, we need to isolate xx on one side of the equation.
Multiply both sides of the equation by 3:
32x3=3373 \cdot \frac{2x}{3} = 3 \cdot \frac{3}{7}
2x=972x = \frac{9}{7}
Now, divide both sides by 2:
2x2=97÷2\frac{2x}{2} = \frac{9}{7} \div 2
x=9712x = \frac{9}{7} \cdot \frac{1}{2}
x=914x = \frac{9}{14}

3. Final Answer

x=914x = \frac{9}{14}

Related problems in "Algebra"

The problem asks us to find the value of $x$ given that the perimeter $P$ of the trapezoid is 41 yar...

PerimeterTrapezoidLinear EquationsSolving Equations
2025/4/6

The problem describes a rectangle with length $3n+2$ and width $n-1$. The perimeter of the rectangle...

PerimeterRectangleLinear Equations
2025/4/6

The problem asks to write the equation of the given line in slope-intercept form, which is $y = mx +...

Linear EquationsSlope-intercept formSlopeY-interceptCoordinate Geometry
2025/4/6

The problem asks us to provide a two-column proof to show that if $25 = -7(y - 3) + 5y$, then $-2 = ...

Linear EquationsEquation SolvingProofProperties of Equality
2025/4/6

The problem asks to prove that if $25 = -7(y - 3) + 5y$, then $y = -2$.

Linear EquationsEquation SolvingSimplification
2025/4/6

The problem states that if $x = 5$ and $b = 5$, then we need to determine if $x = b$.

VariablesEqualitySubstitution
2025/4/6

The problem states that if $2x = 5$, then we need to find the value of $x$.

Linear EquationsSolving Equations
2025/4/6

Solve for $x$ in the equation $(\frac{1}{3})^{\frac{x^2 - 2x}{16 - 2x^2}} = \sqrt[4x]{9}$.

Exponents and RadicalsEquationsSolving EquationsCubic Equations
2025/4/6

We are given that $a$ and $b$ are whole numbers such that $a^b = 121$. We need to evaluate $(a-1)^{b...

ExponentsEquationsInteger Solutions
2025/4/6

The problem is to solve the equation $(x+1)^{\log(x+1)} = 100(x+1)$. It is assumed the base of the ...

LogarithmsEquationsExponentsSolving EquationsAlgebraic Manipulation
2025/4/6