The problem asks to write the equation of the given line in slope-intercept form, which is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

1. Problem Description

The problem asks to write the equation of the given line in slope-intercept form, which is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

2. Solution Steps

First, find the y-intercept. From the graph, the line intersects the y-axis at $(0, 7)$. Thus, the y-intercept $b = 7$.

Next, find the slope of the line. We can pick two points on the line to calculate the slope. Let's choose the points $(0, 7)$ and $(1, 4)$.

The slope $m$ is given by the formula:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Using the points $(0, 7)$ and $(1, 4)$, we have:

$m = \frac{4 - 7}{1 - 0} = \frac{-3}{1} = -3$

Now that we have the slope $m = -3$ and the y-intercept $b = 7$, we can write the equation of the line in slope-intercept form:

$y = mx + b$

$y = -3x + 7$

3. Final Answer

$y = -3x + 7$