The problem asks us to find the quadratic equation whose roots are $-2q$ and $5q$.

AlgebraQuadratic EquationsRoots of EquationsAlgebraic Manipulation
2025/4/11

1. Problem Description

The problem asks us to find the quadratic equation whose roots are 2q-2q and 5q5q.

2. Solution Steps

A quadratic equation with roots r1r_1 and r2r_2 can be written in the form:
x2(r1+r2)x+r1r2=0x^2 - (r_1 + r_2)x + r_1r_2 = 0
In our case, r1=2qr_1 = -2q and r2=5qr_2 = 5q.
First, find the sum of the roots:
r1+r2=2q+5q=3qr_1 + r_2 = -2q + 5q = 3q
Next, find the product of the roots:
r1r2=(2q)(5q)=10q2r_1r_2 = (-2q)(5q) = -10q^2
Substitute these values into the quadratic equation formula:
x2(3q)x+(10q2)=0x^2 - (3q)x + (-10q^2) = 0
x23qx10q2=0x^2 - 3qx - 10q^2 = 0

3. Final Answer

The quadratic equation is x23qx10q2=0x^2 - 3qx - 10q^2 = 0. Therefore, the answer is D.

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