The problem asks to divide the polynomial $108m^3n - 122mn + 48mn^2$ by $2mn$.

AlgebraPolynomial DivisionAlgebraic ManipulationExponents
2025/4/21

1. Problem Description

The problem asks to divide the polynomial 108m3n122mn+48mn2108m^3n - 122mn + 48mn^2 by 2mn2mn.

2. Solution Steps

We divide each term of the polynomial by 2mn2mn:
108m3n122mn+48mn22mn=108m3n2mn122mn2mn+48mn22mn\frac{108m^3n - 122mn + 48mn^2}{2mn} = \frac{108m^3n}{2mn} - \frac{122mn}{2mn} + \frac{48mn^2}{2mn}
Now, we simplify each term:
108m3n2mn=1082m3mnn=54m2\frac{108m^3n}{2mn} = \frac{108}{2} \cdot \frac{m^3}{m} \cdot \frac{n}{n} = 54m^2
122mn2mn=1222mmnn=61\frac{122mn}{2mn} = \frac{122}{2} \cdot \frac{m}{m} \cdot \frac{n}{n} = 61
48mn22mn=482mmn2n=24n\frac{48mn^2}{2mn} = \frac{48}{2} \cdot \frac{m}{m} \cdot \frac{n^2}{n} = 24n
Therefore,
108m3n122mn+48mn22mn=54m261+24n\frac{108m^3n - 122mn + 48mn^2}{2mn} = 54m^2 - 61 + 24n.

3. Final Answer

54m261+24n54m^2 - 61 + 24n

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