We are given a rectangular city on a grid. We are told that in 2006, the city's population was 567,000 people. We need to find the population density in 2006. The population density is defined as the number of people per square kilometer.

Applied MathematicsArea CalculationPopulation DensityUnits Conversion
2025/4/21

1. Problem Description

We are given a rectangular city on a grid. We are told that in 2006, the city's population was 567,000 people. We need to find the population density in
2
0
0

6. The population density is defined as the number of people per square kilometer.

2. Solution Steps

First, we need to determine the dimensions of the rectangle from the graph.
The length of the rectangle along the x-axis (km) goes from 0 to
5

0. Therefore the length is $50 - 0 = 50$ km.

The width of the rectangle along the y-axis (km) goes from 0 to
3

0. Therefore, the width is $30 - 0 = 30$ km.

Next, we need to find the area of the rectangular city.
The area of a rectangle is given by:
Area=lengthwidthArea = length * width
Area=50 km30 km=1500 km2Area = 50 \text{ km} * 30 \text{ km} = 1500 \text{ km}^2
Now we can calculate the population density.
Population density is given by:
Population density=PopulationAreaPopulation \text{ } density = \frac{Population}{Area}
Population density=567,000 people1500 km2=378peoplekm2Population \text{ } density = \frac{567,000 \text{ people}}{1500 \text{ km}^2} = 378 \frac{\text{people}}{\text{km}^2}

3. Final Answer

378 people/km^2

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