The problem asks to find the density of a rectangular prism with a given mass of 48.3 kg and dimensions of 3 m, 2 m, and 7 m.

1. Problem Description

The problem asks to find the density of a rectangular prism with a given mass of 48.3 kg and dimensions of 3 m, 2 m, and 7 m.

2. Solution Steps

First, we need to calculate the volume of the rectangular prism. The volume $V$ of a rectangular prism is given by the formula:

$V = l \times w \times h$

where $l$ is the length, $w$ is the width, and $h$ is the height. In this case, $l = 3$ m, $w = 2$ m, and $h = 7$ m.

$V = 3 \times 2 \times 7 = 42 \, m^3$

Next, we calculate the density. Density, $\rho$, is defined as mass per unit volume:

$\rho = \frac{m}{V}$

where $m$ is the mass and $V$ is the volume. In this case, $m = 48.3$ kg and $V = 42 \, m^3$.

$\rho = \frac{48.3}{42} \approx 1.15 \, kg/m^3$

3. Final Answer

1.15 kg/m^3