We are given a rectangular prism of wood with width 0.4 m, length 0.6 m, and height 0.7 m. The mass of the wood is 63 kg. We need to find the density of the wood in $kg/m^3$.

1. Problem Description

We are given a rectangular prism of wood with width 0.4 m, length 0.6 m, and height 0.7 m. The mass of the wood is 63 kg. We need to find the density of the wood in $kg/m^3$.

2. Solution Steps

The density of an object is defined as its mass divided by its volume.

$Density = \frac{Mass}{Volume}$

First, we need to calculate the volume of the rectangular prism. The volume of a rectangular prism is given by:

$Volume = width \times length \times height$

Plugging in the given values:

$Volume = 0.4 m \times 0.6 m \times 0.7 m = 0.168 m^3$

Now we can calculate the density:

$Density = \frac{63 kg}{0.168 m^3} = 375 kg/m^3$

3. Final Answer

375 $kg/m^3$