The problem asks to find the volume of steel used to create a ball bearing that is in the shape of a sphere with a radius of 12 millimeters. The final answer should be rounded to the nearest tenth of a cubic millimeter.

1. Problem Description

The problem asks to find the volume of steel used to create a ball bearing that is in the shape of a sphere with a radius of 12 millimeters. The final answer should be rounded to the nearest tenth of a cubic millimeter.

2. Solution Steps

The volume of a sphere is given by the formula:

$V = \frac{4}{3} \pi r^3$

where $V$ is the volume and $r$ is the radius of the sphere. In this case, $r = 12$ mm. Plugging this value into the formula, we get:

$V = \frac{4}{3} \pi (12)^3$

$V = \frac{4}{3} \pi (1728)$

$V = 4 \pi (576)$

$V = 2304 \pi$

Now, we can approximate $\pi$ as 3.14159:

$V \approx 2304 \times 3.14159$

$V \approx 7238.22976$

Rounding to the nearest tenth of a cubic millimeter, we get:

$V \approx 7238.2$ mm$^3$

3. Final Answer

The amount of steel used to create each ball bearing is approximately 7238.2 cubic millimeters.