The problem asks us to combine the expression $3\sqrt{3x} + 4\sqrt{75x} + 3\sqrt{48x}$, assuming that $x$ represents a nonnegative real number. We need to simplify the expression and type an exact answer using radicals as needed.

AlgebraRadicalsSimplificationAlgebraic Expressions
2025/4/21

1. Problem Description

The problem asks us to combine the expression 33x+475x+348x3\sqrt{3x} + 4\sqrt{75x} + 3\sqrt{48x}, assuming that xx represents a nonnegative real number. We need to simplify the expression and type an exact answer using radicals as needed.

2. Solution Steps

We first simplify the radicals 75x\sqrt{75x} and 48x\sqrt{48x}.
75x=253x=253x=53x\sqrt{75x} = \sqrt{25 \cdot 3x} = \sqrt{25} \cdot \sqrt{3x} = 5\sqrt{3x}
48x=163x=163x=43x\sqrt{48x} = \sqrt{16 \cdot 3x} = \sqrt{16} \cdot \sqrt{3x} = 4\sqrt{3x}
Substituting these simplified expressions back into the original expression, we have:
33x+475x+348x=33x+4(53x)+3(43x)3\sqrt{3x} + 4\sqrt{75x} + 3\sqrt{48x} = 3\sqrt{3x} + 4(5\sqrt{3x}) + 3(4\sqrt{3x})
=33x+203x+123x = 3\sqrt{3x} + 20\sqrt{3x} + 12\sqrt{3x}
=(3+20+12)3x = (3 + 20 + 12)\sqrt{3x}
=353x = 35\sqrt{3x}

3. Final Answer

353x35\sqrt{3x}

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