We are asked to solve the following system of linear equations by graphing: $y = -x + 4$ $x + y = -\frac{1}{2}$

AlgebraLinear EquationsSystems of EquationsGraphingSlope-intercept formParallel LinesNo Solution
2025/3/17

1. Problem Description

We are asked to solve the following system of linear equations by graphing:
y=x+4y = -x + 4
x+y=12x + y = -\frac{1}{2}

2. Solution Steps

First, we rewrite the second equation to isolate y:
x+y=12x + y = -\frac{1}{2}
y=x12y = -x - \frac{1}{2}
Now we have two equations in slope-intercept form (y=mx+by = mx + b):
y=x+4y = -x + 4
y=x12y = -x - \frac{1}{2}
The first equation has a slope of -1 and a y-intercept of

4. The second equation has a slope of -1 and a y-intercept of $-\frac{1}{2}$.

Since the slopes of the two lines are equal (-1) and the y-intercepts are different (4 and 12-\frac{1}{2}), the lines are parallel. Parallel lines never intersect. Therefore, there is no solution to this system of equations.

3. Final Answer

No solution.

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