The problem asks us to find the domain of the function $d(x) = 4 - \frac{1}{5}x$ for the range $\{0, \frac{11}{5}, 4.5\}$. This means we need to find the corresponding $x$ values for each of the given $d(x)$ values.

AlgebraFunctionsLinear FunctionsDomain and Range
2025/4/21

1. Problem Description

The problem asks us to find the domain of the function d(x)=415xd(x) = 4 - \frac{1}{5}x for the range {0,115,4.5}\{0, \frac{11}{5}, 4.5\}. This means we need to find the corresponding xx values for each of the given d(x)d(x) values.

2. Solution Steps

We have the function d(x)=415xd(x) = 4 - \frac{1}{5}x. We are given the range values d(x)=0d(x) = 0, d(x)=115d(x) = \frac{11}{5}, and d(x)=4.5d(x) = 4.5. We need to find the corresponding xx values for each of these.
First, let d(x)=0d(x) = 0:
0=415x0 = 4 - \frac{1}{5}x
15x=4\frac{1}{5}x = 4
x=4×5=20x = 4 \times 5 = 20
Next, let d(x)=115d(x) = \frac{11}{5}:
115=415x\frac{11}{5} = 4 - \frac{1}{5}x
115=20515x\frac{11}{5} = \frac{20}{5} - \frac{1}{5}x
15x=205115=95\frac{1}{5}x = \frac{20}{5} - \frac{11}{5} = \frac{9}{5}
x=95×5=9x = \frac{9}{5} \times 5 = 9
Finally, let d(x)=4.5=92d(x) = 4.5 = \frac{9}{2}:
92=415x\frac{9}{2} = 4 - \frac{1}{5}x
92=8215x\frac{9}{2} = \frac{8}{2} - \frac{1}{5}x
15x=8292=12\frac{1}{5}x = \frac{8}{2} - \frac{9}{2} = -\frac{1}{2}
x=12×5=52=2.5x = -\frac{1}{2} \times 5 = -\frac{5}{2} = -2.5
So, the domain values are 20,9,2.520, 9, -2.5.

3. Final Answer

{20,9,2.5}\{20, 9, -2.5\}

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