The problem is to graph the function $f(x) = \frac{4}{5}x + 6$. This is a linear function in the form $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

AlgebraLinear FunctionsGraphingSlope-Intercept FormCoordinate Geometry
2025/4/21

1. Problem Description

The problem is to graph the function f(x)=45x+6f(x) = \frac{4}{5}x + 6. This is a linear function in the form y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.

2. Solution Steps

First, identify the slope and y-intercept.
The slope m=45m = \frac{4}{5}.
The y-intercept b=6b = 6. This means the line crosses the y-axis at the point (0,6)(0, 6).
Now, find another point on the line. We can use the slope to find another point. Starting from the y-intercept (0,6)(0, 6), we can go "rise over run". In this case the rise is 4 and the run is

5. Therefore, from $(0, 6)$, move 5 units to the right and 4 units up to find the next point on the line. This gives us the point $(0+5, 6+4) = (5, 10)$.

Alternatively, we could pick an x value, such as x=5x=5, and plug it into the equation:
f(5)=45(5)+6=4+6=10f(5) = \frac{4}{5}(5) + 6 = 4 + 6 = 10. Thus, the point (5,10)(5, 10) is on the line.
Graph the line by plotting the y-intercept (0,6)(0, 6) and the point (5,10)(5, 10) and drawing a straight line through them.

3. Final Answer

The graph of the function f(x)=45x+6f(x) = \frac{4}{5}x + 6 is a straight line that passes through the points (0,6)(0, 6) and (5,10)(5, 10). I would plot these two points on a graph and draw a line connecting them.

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