The problem is to remove the brackets and simplify the given expressions. I will solve question number 14: $(7y-1)(7y+1)$.

AlgebraAlgebraic ManipulationExpansionDifference of Squares
2025/6/19

1. Problem Description

The problem is to remove the brackets and simplify the given expressions. I will solve question number 14: (7y1)(7y+1)(7y-1)(7y+1).

2. Solution Steps

We need to expand the expression (7y1)(7y+1)(7y-1)(7y+1). This is in the form of (ab)(a+b)(a-b)(a+b), which is a difference of squares. We can use the following formula:
(ab)(a+b)=a2b2(a-b)(a+b) = a^2 - b^2
Here, a=7ya=7y and b=1b=1.
So, we have:
(7y1)(7y+1)=(7y)2(1)2(7y-1)(7y+1) = (7y)^2 - (1)^2
(7y)2=49y2(7y)^2 = 49y^2
(1)2=1(1)^2 = 1
Therefore,
(7y1)(7y+1)=49y21(7y-1)(7y+1) = 49y^2 - 1

3. Final Answer

49y2149y^2 - 1

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