The problem asks to find the y-intercept and the slope of the given line, and then to write the equation of the line in slope-intercept form.

AlgebraLinear EquationsSlopeY-interceptSlope-intercept form
2025/4/21

1. Problem Description

The problem asks to find the y-intercept and the slope of the given line, and then to write the equation of the line in slope-intercept form.

2. Solution Steps

First, we determine the y-intercept of the line. The line intersects the y-axis at the point (0, -3). Therefore, the y-intercept is -
3.
Next, we determine the slope of the line. We need to find two points on the line. From the graph, we can choose the points (0, -3) and (2, -1).
The formula for the slope mm is:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
Using the points (0, -3) and (2, -1), we have x1=0x_1 = 0, y1=3y_1 = -3, x2=2x_2 = 2, and y2=1y_2 = -1.
Plugging these values into the formula, we get:
m=1(3)20=1+32=22=1m = \frac{-1 - (-3)}{2 - 0} = \frac{-1 + 3}{2} = \frac{2}{2} = 1
Therefore, the slope of the line is
1.
Now, we need to write the equation of the line in slope-intercept form, which is:
y=mx+by = mx + b
where mm is the slope and bb is the y-intercept.
We found that m=1m = 1 and b=3b = -3. Substituting these values into the equation, we get:
y=1x+(3)y = 1x + (-3)
y=x3y = x - 3

3. Final Answer

The y-intercept of the line is at (0, -3).
The slope of the line is

1. The equation of the line is $y = x - 3$.

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