The problem asks to graph the linear equation $y = 4x - 3$.

1. Problem Description

The problem asks to graph the linear equation $y = 4x - 3$.

2. Solution Steps

To graph the line $y = 4x - 3$, we need to find at least two points on the line.

First, let's find the y-intercept. This occurs when $x = 0$.

$y = 4(0) - 3 = -3$. So the y-intercept is at the point $(0, -3)$.

Next, let's find another point on the line. Let's choose $x = 1$.

$y = 4(1) - 3 = 4 - 3 = 1$. So the point $(1, 1)$ is on the line.

We can also compute the x-intercept, which occurs when $y=0$:

$0 = 4x - 3$

$4x = 3$

$x = \frac{3}{4} = 0.75$. So the x-intercept is at the point $(0.75, 0)$.

The slope of the line is $4$. This means that for every increase of $1$ in the x-value, the y-value increases by $4$.

3. Final Answer

The graph of the equation $y = 4x - 3$ is a straight line that passes through the points $(0, -3)$ and $(1, 1)$.