We are given four sets: $A = \{1, 2, 3, 4, 5, 6\}$, $B = \{2, 4, 6\}$, $C = \{1, 2, 3\}$, and $D = \{7, 8, 9\}$. The universe set is $U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}$. We need to find the complement of the union of sets $B$ and $C$, which is $(B \cup C)^c$.

Discrete MathematicsSet TheorySet OperationsUnionComplement
2025/4/22

1. Problem Description

We are given four sets: A={1,2,3,4,5,6}A = \{1, 2, 3, 4, 5, 6\}, B={2,4,6}B = \{2, 4, 6\}, C={1,2,3}C = \{1, 2, 3\}, and D={7,8,9}D = \{7, 8, 9\}. The universe set is U={1,2,3,4,5,6,7,8,9,10}U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}. We need to find the complement of the union of sets BB and CC, which is (BC)c(B \cup C)^c.

2. Solution Steps

First, we find the union of sets BB and CC.
BCB \cup C is the set of all elements that are in BB or in CC or in both.
B={2,4,6}B = \{2, 4, 6\} and C={1,2,3}C = \{1, 2, 3\}.
BC={1,2,3,4,6}B \cup C = \{1, 2, 3, 4, 6\}.
Next, we find the complement of BCB \cup C with respect to the universe set UU.
(BC)c(B \cup C)^c is the set of all elements in UU that are not in BCB \cup C.
U={1,2,3,4,5,6,7,8,9,10}U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\} and BC={1,2,3,4,6}B \cup C = \{1, 2, 3, 4, 6\}.
Thus, (BC)c={5,7,8,9,10}(B \cup C)^c = \{5, 7, 8, 9, 10\}.

3. Final Answer

(BC)c={5,7,8,9,10}(B \cup C)^c = \{5, 7, 8, 9, 10\}

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