The problem provides an incomplete Pascal code snippet that aims to display multiples of 5 below 50. The task is to fill in the missing code parts, labeled with numbers from 1 to 4, to complete the program. The corrected code will print multiples of 5 that are less than 50.
2025/3/17
1. Problem Description
The problem provides an incomplete Pascal code snippet that aims to display multiples of 5 below
5
0. The task is to fill in the missing code parts, labeled with numbers from 1 to 4, to complete the program. The corrected code will print multiples of 5 that are less than
5
0.
2. Solution Steps
The Pascal code is intended to print multiples of 5 less than
5
0. Let's identify the missing parts and fill them in:
* (1): The variable declaration `var x:`; needs a type. Since we are dealing with integers (multiples of 5), it should be an integer type.
```pascal
var x: integer;
```
* (2): The initial value of `x` is missing. To start the loop with multiples of 5, the variable x should be initialized to
5. ```pascal
x := 5;
```
* (3): The `while` loop condition is `x < 50 do`, so this line looks fine.
* (4): Inside the loop, before incrementing `x`, the current value of `x` (a multiple of 5) needs to be printed. We can use the `writeln` function for this.
```pascal
writeln(x);
```
3. Final Answer
The complete code with the missing parts filled in is:
```pascal
Program x1;
var x: integer;
begin
x := 5;
while x < 50 do
begin
writeln(x);
x := x + 5;
end;
readln();
end.
```
Therefore, the missing codes are: