We need to find the slope of the line given by the equation $2y + 3x = 13$.

AlgebraLinear EquationsSlope-intercept form
2025/4/22

1. Problem Description

We need to find the slope of the line given by the equation 2y+3x=132y + 3x = 13.

2. Solution Steps

First, we rewrite the equation in the slope-intercept form, which is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
2y+3x=132y + 3x = 13
Subtract 3x3x from both sides:
2y=3x+132y = -3x + 13
Divide both sides by 2:
y=32x+132y = -\frac{3}{2}x + \frac{13}{2}
Now, we can identify the slope mm from the slope-intercept form y=mx+by = mx + b.
In this case, m=32m = -\frac{3}{2}.

3. Final Answer

The slope of the line is m=32m = -\frac{3}{2}.
The answer is d) m=32m = -\frac{3}{2}.

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