The image shows "1) 150mL -> HI". This means we are asked to convert 150 milliliters (mL) to a unit associated with HI (presumably related to concentration). Without further context regarding the concentration or molarity of HI, or what specific unit the problem expects for the answer, it is impossible to provide a numerical answer. The arrow seems to imply converting 150 mL to something that involves HI.

1. Problem Description

The image shows "1) 150mL -> HI". This means we are asked to convert 150 milliliters (mL) to a unit associated with HI (presumably related to concentration). Without further context regarding the concentration or molarity of HI, or what specific unit the problem expects for the answer, it is impossible to provide a numerical answer. The arrow seems to imply converting 150 mL to something that involves HI.

2. Solution Steps

Since we lack information about the molarity or concentration of HI, and also the intended units to which we want to convert 150 mL, it is impossible to provide a full numerical solution. However, let's consider some possibilities and explain what additional information would be needed to complete the conversion:

Possibility 1: Convert to moles of HI if we know the molarity.

Suppose the solution has a molarity $M$ (in moles/L). Then we know:

$M = \frac{\text{moles of HI}}{\text{Liters of solution}}$

To find moles of HI, we would first convert 150 mL to liters:

$150 \text{ mL} = 150 \text{ mL} \times \frac{1 \text{ L}}{1000 \text{ mL}} = 0.15 \text{ L}$

Then, moles of HI = $M \times 0.15$

Possibility 2: Convert to grams of HI if we know the concentration in g/mL.

Suppose the concentration is $C$ (in grams/mL). Then:

grams of HI = $C \times \text{volume in mL}$

grams of HI = $C \times 150$

Possibility 3: Convert to number of HI molecules, if the molarity is known.

First convert mL to L as shown above.

Then calculate the moles of HI using $M$.

After that use Avogadro's number ($6.022 \times 10^{23}$ molecules/mol) to convert moles to number of molecules.

Number of HI molecules = moles of HI $\times 6.022 \times 10^{23}$

Without a specific molarity or concentration, or intended units for the converted value, we cannot calculate a numerical answer.

3. Final Answer

Insufficient information to provide a numerical answer. We need the concentration or molarity of HI, and the units to convert to.