The problem asks us to find the intercepts of a line, using its equation or any other method. However, the equation of the line is not provided in the image. Therefore, I can only describe how to find the intercepts given an equation. If the equation were provided, I could directly compute the intercepts. I will assume the equation is $y = mx + b$.

1. Problem Description

The problem asks us to find the intercepts of a line, using its equation or any other method. However, the equation of the line is not provided in the image. Therefore, I can only describe how to find the intercepts given an equation. If the equation were provided, I could directly compute the intercepts. I will assume the equation is $y = mx + b$.

2. Solution Steps

To find the y-intercept, we set $x = 0$ in the equation of the line and solve for $y$. The y-intercept is the point where the line crosses the y-axis, which occurs when $x=0$. So, if the equation is $y = mx + b$, substituting $x=0$ gives $y = m(0) + b = b$. Thus, the y-intercept is at $(0, b)$.

To find the x-intercept, we set $y = 0$ in the equation of the line and solve for $x$. The x-intercept is the point where the line crosses the x-axis, which occurs when $y=0$. If the equation is $y = mx + b$, setting $y=0$ gives $0 = mx + b$. Solving for $x$ gives $mx = -b$, so $x = -b/m$. Thus, the x-intercept is at $(-b/m, 0)$.

3. Final Answer

If the equation of the line is $y = mx + b$, then the y-intercept is $(0, b)$ and the x-intercept is $(-b/m, 0)$. Since the equation is not given, I can only describe how to calculate the intercepts in terms of the slope and y-intercept.