We are asked to solve the equation $5^{2-x} = \frac{1}{125}$ for $x$.

AlgebraExponentsEquationsExponential EquationsAlgebraic Manipulation
2025/4/23

1. Problem Description

We are asked to solve the equation 52x=11255^{2-x} = \frac{1}{125} for xx.

2. Solution Steps

We are given the equation 52x=11255^{2-x} = \frac{1}{125}. We can rewrite 1125\frac{1}{125} as a power of

5. Since $125 = 5^3$, we have $\frac{1}{125} = \frac{1}{5^3} = 5^{-3}$.

Therefore, our equation becomes 52x=535^{2-x} = 5^{-3}.
Since the bases are equal, we can equate the exponents:
2x=32 - x = -3
Now we solve for xx:
2x=32 - x = -3
Subtract 2 from both sides:
x=32-x = -3 - 2
x=5-x = -5
Multiply both sides by -1:
x=5x = 5

3. Final Answer

The solution to the equation 52x=11255^{2-x} = \frac{1}{125} is x=5x=5.

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