The problem is to simplify the expression $D = \sqrt{\frac{2}{1+sin\alpha} + \frac{2}{1-sin\alpha}}$.

AlgebraTrigonometrySimplificationAlgebraic ManipulationTrigonometric IdentitiesSquare Roots
2025/4/24

1. Problem Description

The problem is to simplify the expression D=21+sinα+21sinαD = \sqrt{\frac{2}{1+sin\alpha} + \frac{2}{1-sin\alpha}}.

2. Solution Steps

First, combine the two fractions inside the square root by finding a common denominator.
D=2(1sinα)+2(1+sinα)(1+sinα)(1sinα)D = \sqrt{\frac{2(1-sin\alpha) + 2(1+sin\alpha)}{(1+sin\alpha)(1-sin\alpha)}}
D=22sinα+2+2sinα1sin2αD = \sqrt{\frac{2 - 2sin\alpha + 2 + 2sin\alpha}{1 - sin^2\alpha}}
D=41sin2αD = \sqrt{\frac{4}{1 - sin^2\alpha}}
We know the trigonometric identity:
sin2α+cos2α=1sin^2\alpha + cos^2\alpha = 1
cos2α=1sin2αcos^2\alpha = 1 - sin^2\alpha
Substitute cos2αcos^2\alpha for 1sin2α1 - sin^2\alpha:
D=4cos2αD = \sqrt{\frac{4}{cos^2\alpha}}
D=4cos2αD = \frac{\sqrt{4}}{\sqrt{cos^2\alpha}}
D=2cosαD = \frac{2}{|cos\alpha|}

3. Final Answer

D=2cosαD = \frac{2}{|cos\alpha|}

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