The problem is to solve the following linear equation for $n$: $5(n+2) - 15 = 4 - (2n - 5)$

AlgebraLinear EquationsEquation SolvingAlgebraic Manipulation
2025/4/26

1. Problem Description

The problem is to solve the following linear equation for nn:
5(n+2)15=4(2n5)5(n+2) - 15 = 4 - (2n - 5)

2. Solution Steps

We want to solve the equation 5(n+2)15=4(2n5)5(n+2) - 15 = 4 - (2n - 5) for nn.
First, we distribute the numbers outside the parentheses:
5n+1015=42n+55n + 10 - 15 = 4 - 2n + 5
Combine the constant terms on both sides of the equation:
5n5=92n5n - 5 = 9 - 2n
Add 2n2n to both sides of the equation:
5n+2n5=92n+2n5n + 2n - 5 = 9 - 2n + 2n
7n5=97n - 5 = 9
Add 5 to both sides of the equation:
7n5+5=9+57n - 5 + 5 = 9 + 5
7n=147n = 14
Divide both sides by 7:
7n7=147\frac{7n}{7} = \frac{14}{7}
n=2n = 2

3. Final Answer

n=2n = 2

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