The problem asks to solve two equations. Equation 1: $5(n+2)-15 = 4-(2n-5)$ Equation 2: $2x+5=6x-3$

1. Problem Description

The problem asks to solve two equations.

Equation 1: $5(n+2)-15 = 4-(2n-5)$

Equation 2: $2x+5=6x-3$

2. Solution Steps

Equation 1: $5(n+2)-15 = 4-(2n-5)$

First, distribute the constants into the parentheses.

$5n + 10 - 15 = 4 - 2n + 5$

Simplify both sides.

$5n - 5 = 9 - 2n$

Add $2n$ to both sides.

$5n + 2n - 5 = 9 - 2n + 2n$

$7n - 5 = 9$

Add 5 to both sides.

$7n - 5 + 5 = 9 + 5$

$7n = 14$

Divide both sides by

7. $\frac{7n}{7} = \frac{14}{7}$

$n = 2$

Equation 2: $2x+5=6x-3$

Subtract $2x$ from both sides.

$2x - 2x + 5 = 6x - 2x - 3$

$5 = 4x - 3$

Add 3 to both sides.

$5 + 3 = 4x - 3 + 3$

$8 = 4x$

Divide both sides by

4. $\frac{8}{4} = \frac{4x}{4}$

$2 = x$

$x = 2$

3. Final Answer

The solution to the first equation is $n=2$.

The solution to the second equation is $x=2$.