We are asked to expand the expression $(x+4y)(x-3y)$.AlgebraPolynomial ExpansionDistributive PropertyFOIL Method2025/4/271. Problem DescriptionWe are asked to expand the expression (x+4y)(x−3y)(x+4y)(x-3y)(x+4y)(x−3y).2. Solution StepsTo expand the expression (x+4y)(x−3y)(x+4y)(x-3y)(x+4y)(x−3y), we use the distributive property (also known as the FOIL method):(x+4y)(x−3y)=x(x)+x(−3y)+4y(x)+4y(−3y)(x+4y)(x-3y) = x(x) + x(-3y) + 4y(x) + 4y(-3y)(x+4y)(x−3y)=x(x)+x(−3y)+4y(x)+4y(−3y)=x2−3xy+4xy−12y2= x^2 - 3xy + 4xy - 12y^2=x2−3xy+4xy−12y2=x2+(4xy−3xy)−12y2= x^2 + (4xy - 3xy) - 12y^2=x2+(4xy−3xy)−12y2=x2+xy−12y2= x^2 + xy - 12y^2=x2+xy−12y23. Final Answerx2+xy−12y2x^2 + xy - 12y^2x2+xy−12y2