The problem asks to expand the product of two binomials: $(2x + y)(4x + 3y)$.

AlgebraPolynomial ExpansionBinomial MultiplicationAlgebraic Manipulation
2025/4/27

1. Problem Description

The problem asks to expand the product of two binomials: (2x+y)(4x+3y)(2x + y)(4x + 3y).

2. Solution Steps

We can use the distributive property (also known as FOIL method) to expand the expression.
(2x+y)(4x+3y)=(2x)(4x)+(2x)(3y)+(y)(4x)+(y)(3y)(2x + y)(4x + 3y) = (2x)(4x) + (2x)(3y) + (y)(4x) + (y)(3y)
Now, we multiply the terms:
(2x)(4x)=8x2(2x)(4x) = 8x^2
(2x)(3y)=6xy(2x)(3y) = 6xy
(y)(4x)=4xy(y)(4x) = 4xy
(y)(3y)=3y2(y)(3y) = 3y^2
Substitute these back into the equation:
8x2+6xy+4xy+3y28x^2 + 6xy + 4xy + 3y^2
Combine the like terms (the xyxy terms):
6xy+4xy=10xy6xy + 4xy = 10xy
So the expression becomes:
8x2+10xy+3y28x^2 + 10xy + 3y^2

3. Final Answer

8x2+10xy+3y28x^2 + 10xy + 3y^2

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