The problem is to expand the product of two binomials: $(2x - 5y)(3x - 2y)$.

AlgebraPolynomial ExpansionBinomialsDistributive PropertyFOIL Method
2025/4/27

1. Problem Description

The problem is to expand the product of two binomials: (2x5y)(3x2y)(2x - 5y)(3x - 2y).

2. Solution Steps

We use the distributive property (also known as the FOIL method) to expand the product:
(a+b)(c+d)=ac+ad+bc+bd(a + b)(c + d) = ac + ad + bc + bd
Applying this to our problem:
(2x5y)(3x2y)=(2x)(3x)+(2x)(2y)+(5y)(3x)+(5y)(2y)(2x - 5y)(3x - 2y) = (2x)(3x) + (2x)(-2y) + (-5y)(3x) + (-5y)(-2y)
Now, we perform each multiplication:
(2x)(3x)=6x2(2x)(3x) = 6x^2
(2x)(2y)=4xy(2x)(-2y) = -4xy
(5y)(3x)=15xy(-5y)(3x) = -15xy
(5y)(2y)=10y2(-5y)(-2y) = 10y^2
So we have:
6x24xy15xy+10y26x^2 - 4xy - 15xy + 10y^2
Combine the like terms 4xy-4xy and 15xy-15xy:
4xy15xy=19xy-4xy - 15xy = -19xy
Therefore, the expression simplifies to:
6x219xy+10y26x^2 - 19xy + 10y^2

3. Final Answer

6x219xy+10y26x^2 - 19xy + 10y^2

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