We can rewrite the expression as follows:
(a−b−c)2=(a−(b+c))2 We can use the formula for the square of a difference:
(x−y)2=x2−2xy+y2 In our case, x=a and y=b+c. So,
(a−(b+c))2=a2−2a(b+c)+(b+c)2 Now, we need to expand (b+c)2: (b+c)2=b2+2bc+c2 Substitute this back into the expression:
a2−2a(b+c)+(b+c)2=a2−2ab−2ac+b2+2bc+c2 Rearranging the terms, we get:
a2+b2+c2−2ab−2ac+2bc