We need to expand the expression $(x - y + 3)(x - y - 3)$.

AlgebraAlgebraic ExpansionDifference of SquaresPolynomials
2025/4/27

1. Problem Description

We need to expand the expression (xy+3)(xy3)(x - y + 3)(x - y - 3).

2. Solution Steps

Let A=xyA = x - y. Then the expression becomes (A+3)(A3)(A + 3)(A - 3).
This is a difference of squares:
(a+b)(ab)=a2b2(a + b)(a - b) = a^2 - b^2.
So, (A+3)(A3)=A232=A29(A + 3)(A - 3) = A^2 - 3^2 = A^2 - 9.
Substituting back A=xyA = x - y, we have:
(xy)29(x - y)^2 - 9.
Now we expand (xy)2(x - y)^2 using the formula:
(ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2.
So, (xy)2=x22xy+y2(x - y)^2 = x^2 - 2xy + y^2.
Therefore, the expression becomes:
x22xy+y29x^2 - 2xy + y^2 - 9.

3. Final Answer

x22xy+y29x^2 - 2xy + y^2 - 9

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