We can rewrite the expression as follows:
(x+y−z)(x−y−z)=(x−(z−y))(x−(y+z))=((x−z)+y)((x−z)−y). Let u=x−z. Then the expression becomes (u+y)(u−y). Using the difference of squares formula, (a+b)(a−b)=a2−b2, we have (u+y)(u−y)=u2−y2. Substituting u=x−z back into the equation, we get (x−z)2−y2=(x2−2xz+z2)−y2=x2−2xz+z2−y2. Rearranging the terms, we get
x2−y2+z2−2xz. Alternative Approach:
We can expand the product term by term:
(x+y−z)(x−y−z)=x(x−y−z)+y(x−y−z)−z(x−y−z) =x2−xy−xz+yx−y2−yz−zx+zy+z2 =x2−xy−xz+xy−y2−yz−xz+yz+z2 =x2−y2+z2−2xz.