The image presents several math problems: finding the intersection point of pairs of lines and finding the equation of a line that passes through a given point and is parallel to a given line. I will solve problem number 1, finding the intersection point of the lines $x - 2y - 4 = 0$ and $2x + 3y - 1 = 0$.

1. Problem Description

The image presents several math problems: finding the intersection point of pairs of lines and finding the equation of a line that passes through a given point and is parallel to a given line. I will solve problem number 1, finding the intersection point of the lines $x - 2y - 4 = 0$ and $2x + 3y - 1 = 0$.

2. Solution Steps

We need to solve the system of equations:

$x - 2y - 4 = 0$ (1)

$2x + 3y - 1 = 0$ (2)

From equation (1), we can express $x$ in terms of $y$:

$x = 2y + 4$ (3)

Substitute (3) into (2):

$2(2y + 4) + 3y - 1 = 0$

$4y + 8 + 3y - 1 = 0$

$7y + 7 = 0$

$7y = -7$

$y = -1$

Now, substitute $y = -1$ back into (3):

$x = 2(-1) + 4$

$x = -2 + 4$

$x = 2$

Therefore, the intersection point is $(2, -1)$.

3. Final Answer

The intersection point of the lines $x - 2y - 4 = 0$ and $2x + 3y - 1 = 0$ is $(2, -1)$.