The problem states that the point $A'(x+1, -2)$ is the image of the point $A(-4, 2)$ after a rotation of $180^\circ$ around the origin $O$. We need to find the value of $x$.

GeometryCoordinate GeometryRotationTransformations
2025/4/28

1. Problem Description

The problem states that the point A(x+1,2)A'(x+1, -2) is the image of the point A(4,2)A(-4, 2) after a rotation of 180180^\circ around the origin OO. We need to find the value of xx.

2. Solution Steps

When a point (a,b)(a, b) is rotated 180180^\circ about the origin, its image is (a,b)(-a, -b).
Therefore, if A(4,2)A(-4, 2) is rotated 180180^\circ about the origin, its image AA' will be (4,2)(4, -2).
We are given that A(x+1,2)A'(x+1, -2). Therefore, we can equate the x-coordinates:
x+1=4x + 1 = 4
x=41x = 4 - 1
x=3x = 3

3. Final Answer

The value of xx is 3.

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