A 20-tooth pinion drives a 40-tooth gear. The pinion has an angular velocity of 1000 rpm. We need to determine the velocity ratio and the angular velocity of the gear.

Applied MathematicsGearsMechanical EngineeringVelocity RatioAngular Velocity
2025/4/29

1. Problem Description

A 20-tooth pinion drives a 40-tooth gear. The pinion has an angular velocity of 1000 rpm. We need to determine the velocity ratio and the angular velocity of the gear.

2. Solution Steps

The velocity ratio is the ratio of the number of teeth on the gear to the number of teeth on the pinion.
VelocityRatio=NgearNpinionVelocity\,Ratio = \frac{N_{gear}}{N_{pinion}}
where NgearN_{gear} is the number of teeth on the gear and NpinionN_{pinion} is the number of teeth on the pinion.
Given that Ngear=40N_{gear} = 40 and Npinion=20N_{pinion} = 20,
VelocityRatio=4020=2Velocity\,Ratio = \frac{40}{20} = 2
The angular velocity of the gear can be calculated using the following relationship:
NgearNpinion=ωpinionωgear\frac{N_{gear}}{N_{pinion}} = \frac{\omega_{pinion}}{\omega_{gear}}
where ωpinion\omega_{pinion} is the angular velocity of the pinion and ωgear\omega_{gear} is the angular velocity of the gear.
Given that ωpinion=1000rpm\omega_{pinion} = 1000 \, rpm, we can solve for ωgear\omega_{gear}:
ωgear=NpinionNgear×ωpinion\omega_{gear} = \frac{N_{pinion}}{N_{gear}} \times \omega_{pinion}
ωgear=2040×1000rpm\omega_{gear} = \frac{20}{40} \times 1000\, rpm
ωgear=12×1000rpm\omega_{gear} = \frac{1}{2} \times 1000\, rpm
ωgear=500rpm\omega_{gear} = 500\, rpm

3. Final Answer

Velocity Ratio = 2
Angular velocity of the gear = 500 rpm

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