We need to simplify the expression $\frac{4!4!}{2!2!2!2!}$.

ArithmeticFactorialsSimplificationArithmetic Operations
2025/3/18

1. Problem Description

We need to simplify the expression 4!4!2!2!2!2!\frac{4!4!}{2!2!2!2!}.

2. Solution Steps

First, recall the definition of a factorial: n!=n×(n1)×(n2)×...×2×1n! = n \times (n-1) \times (n-2) \times ... \times 2 \times 1.
Then, we evaluate the factorials in the expression.
4!=4×3×2×1=244! = 4 \times 3 \times 2 \times 1 = 24
2!=2×1=22! = 2 \times 1 = 2
Now substitute these values into the expression:
4!4!2!2!2!2!=24×242×2×2×2=57616\frac{4!4!}{2!2!2!2!} = \frac{24 \times 24}{2 \times 2 \times 2 \times 2} = \frac{576}{16}
Finally, we divide 576 by 16:
57616=36\frac{576}{16} = 36

3. Final Answer

36

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