A trader sells yams of three sizes: Big, Medium, and Small. A big yam sells for GH₵12.00, three medium yams sell for GH₵20.00, and five small yams sell for GH₵18.00. On a particular day, the number of medium tubers sold was 15 more than the number of big tubers sold. The number of small tubers sold was twice the number of medium tubers sold. The total sales for that day amounted to GH₵1372.00. The problem asks to find the number of Big, Medium, and Small tubers of yam sold on that day.

AlgebraLinear EquationsWord ProblemsSystems of EquationsArithmetic
2025/4/29

1. Problem Description

A trader sells yams of three sizes: Big, Medium, and Small. A big yam sells for GH₵12.00, three medium yams sell for GH₵20.00, and five small yams sell for GH₵18.
0

0. On a particular day, the number of medium tubers sold was 15 more than the number of big tubers sold. The number of small tubers sold was twice the number of medium tubers sold. The total sales for that day amounted to GH₵1372.

0

0. The problem asks to find the number of Big, Medium, and Small tubers of yam sold on that day.

2. Solution Steps

Let xx be the number of big tubers sold.
The number of medium tubers sold is x+15x + 15.
The number of small tubers sold is 2(x+15)=2x+302(x + 15) = 2x + 30.
The total revenue from big tubers is 12x12x.
The revenue from one medium tuber is 203\frac{20}{3}.
The total revenue from medium tubers is 203(x+15)\frac{20}{3}(x + 15).
The revenue from one small tuber is 185\frac{18}{5}.
The total revenue from small tubers is 185(2x+30)\frac{18}{5}(2x + 30).
The total sales for the day is GH₵1372.
0

0. Therefore, we have:

12x+203(x+15)+185(2x+30)=137212x + \frac{20}{3}(x + 15) + \frac{18}{5}(2x + 30) = 1372
Multiply the equation by 15 to eliminate fractions:
15(12x)+15(203(x+15))+15(185(2x+30))=15(1372)15(12x) + 15(\frac{20}{3}(x + 15)) + 15(\frac{18}{5}(2x + 30)) = 15(1372)
180x+5(20(x+15))+3(18(2x+30))=20580180x + 5(20(x + 15)) + 3(18(2x + 30)) = 20580
180x+100(x+15)+54(2x+30)=20580180x + 100(x + 15) + 54(2x + 30) = 20580
180x+100x+1500+108x+1620=20580180x + 100x + 1500 + 108x + 1620 = 20580
388x+3120=20580388x + 3120 = 20580
388x=205803120388x = 20580 - 3120
388x=17460388x = 17460
x=17460388=45x = \frac{17460}{388} = 45
Number of big tubers sold: x=45x = 45
Number of medium tubers sold: x+15=45+15=60x + 15 = 45 + 15 = 60
Number of small tubers sold: 2(x+15)=2(60)=1202(x + 15) = 2(60) = 120

3. Final Answer

The number of big tubers sold is
4

5. The number of medium tubers sold is

6

0. The number of small tubers sold is

1
2
0.

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