A trader sells yams of three sizes: Big, Medium, and Small. A big yam sells for GH₵12.00, three medium yams sell for GH₵20.00, and five small yams sell for GH₵18.00. On a particular day, the number of medium tubers sold was 15 more than the number of big tubers sold. The number of small tubers sold was twice the number of medium tubers sold. The total sales for that day amounted to GH₵1372.00. The problem asks to find the number of Big, Medium, and Small tubers of yam sold on that day.

AlgebraLinear EquationsWord ProblemsSystems of EquationsArithmetic
2025/4/29

1. Problem Description

A trader sells yams of three sizes: Big, Medium, and Small. A big yam sells for GH₵12.00, three medium yams sell for GH₵20.00, and five small yams sell for GH₵18.
0

0. On a particular day, the number of medium tubers sold was 15 more than the number of big tubers sold. The number of small tubers sold was twice the number of medium tubers sold. The total sales for that day amounted to GH₵1372.

0

0. The problem asks to find the number of Big, Medium, and Small tubers of yam sold on that day.

2. Solution Steps

Let xx be the number of big tubers sold.
The number of medium tubers sold is x+15x + 15.
The number of small tubers sold is 2(x+15)=2x+302(x + 15) = 2x + 30.
The total revenue from big tubers is 12x12x.
The revenue from one medium tuber is 203\frac{20}{3}.
The total revenue from medium tubers is 203(x+15)\frac{20}{3}(x + 15).
The revenue from one small tuber is 185\frac{18}{5}.
The total revenue from small tubers is 185(2x+30)\frac{18}{5}(2x + 30).
The total sales for the day is GH₵1372.
0

0. Therefore, we have:

12x+203(x+15)+185(2x+30)=137212x + \frac{20}{3}(x + 15) + \frac{18}{5}(2x + 30) = 1372
Multiply the equation by 15 to eliminate fractions:
15(12x)+15(203(x+15))+15(185(2x+30))=15(1372)15(12x) + 15(\frac{20}{3}(x + 15)) + 15(\frac{18}{5}(2x + 30)) = 15(1372)
180x+5(20(x+15))+3(18(2x+30))=20580180x + 5(20(x + 15)) + 3(18(2x + 30)) = 20580
180x+100(x+15)+54(2x+30)=20580180x + 100(x + 15) + 54(2x + 30) = 20580
180x+100x+1500+108x+1620=20580180x + 100x + 1500 + 108x + 1620 = 20580
388x+3120=20580388x + 3120 = 20580
388x=205803120388x = 20580 - 3120
388x=17460388x = 17460
x=17460388=45x = \frac{17460}{388} = 45
Number of big tubers sold: x=45x = 45
Number of medium tubers sold: x+15=45+15=60x + 15 = 45 + 15 = 60
Number of small tubers sold: 2(x+15)=2(60)=1202(x + 15) = 2(60) = 120

3. Final Answer

The number of big tubers sold is
4

5. The number of medium tubers sold is

6

0. The number of small tubers sold is

1
2
0.

Related problems in "Algebra"

The problem states that a rectangle has a length of $x$ cm and a width of $(x - 1)$ cm. The perimet...

PerimeterRectanglesLinear EquationsSolving Equations
2025/4/29

The problem asks us to simplify the expression $\frac{2}{2+x} + \frac{2}{2-x}$.

Algebraic ExpressionsSimplificationFractionsDifference of Squares
2025/4/29

The problem asks to simplify the expression $2\sqrt{3} - \frac{6}{\sqrt{3}} + \frac{3}{\sqrt{27}}$.

SimplificationRadicalsRationalizationAlgebraic Manipulation
2025/4/29

We are given the equation $\frac{5^{n+3}}{25^{2n-2}} = 5^0$ and we need to find the value of $n$.

ExponentsEquationsSimplificationProblem Solving
2025/4/29

The problem asks us to solve the inequality $3(x + 1) \le 5(x + 2) + 15$.

InequalitiesLinear InequalitiesSolving Inequalities
2025/4/29

The problem asks to find the value of $x$ such that the sum of 6 and one-third of $x$ is one more th...

Linear EquationsEquation SolvingVariable Isolation
2025/4/29

The problem states that the sum of two consecutive whole numbers is $\frac{5}{6}$ of their product. ...

Word ProblemEquationsNumber PropertiesConsecutive Numbers
2025/4/29

The problem asks us to factorize the expression $x + y - ax - ay$. We need to choose the correct fac...

FactorizationAlgebraic ManipulationCommon Factors
2025/4/29

The problem consists of three parts: a) Simplify the algebraic expression $5(6 - ab) + 2(-7 + 3ab)$....

Algebraic ExpressionsLinear EquationsSlope-intercept formPercentageWord Problems
2025/4/29

The problem has two parts. (a) Simplify the expression $5(6 - ab) + 2(-7 + 3ab)$. (b) Given the equa...

SimplificationLinear EquationsGradientY-interceptAlgebraic Expressions
2025/4/29