The problem contains three sub-problems: a) Find the value of $y$ given the equation $11y = (18)^2 - (15)^2$. b) Find the perimeter of a circle with radius $35$ cm, given $\pi = \frac{22}{7}$. c) i) Make $r$ the subject of the formula $m = \frac{r-s}{2nr}$. ii) Find the value of $r$ when $s=117$, $m=2$, and $n=-3$.

AlgebraEquationsCircle PerimeterFormula ManipulationSubstitution
2025/4/29

1. Problem Description

The problem contains three sub-problems:
a) Find the value of yy given the equation 11y=(18)2(15)211y = (18)^2 - (15)^2.
b) Find the perimeter of a circle with radius 3535 cm, given π=227\pi = \frac{22}{7}.
c) i) Make rr the subject of the formula m=rs2nrm = \frac{r-s}{2nr}.
ii) Find the value of rr when s=117s=117, m=2m=2, and n=3n=-3.

2. Solution Steps

a)
We are given 11y=(18)2(15)211y = (18)^2 - (15)^2.
11y=32422511y = 324 - 225
11y=9911y = 99
y=9911y = \frac{99}{11}
y=9y = 9
b)
The perimeter (circumference) of a circle is given by the formula
C=2πrC = 2\pi r, where rr is the radius.
Given r=35r = 35 cm and π=227\pi = \frac{22}{7},
C=2×227×35C = 2 \times \frac{22}{7} \times 35
C=2×22×5C = 2 \times 22 \times 5
C=44×5C = 44 \times 5
C=220C = 220 cm
c) i)
We are given m=rs2nrm = \frac{r-s}{2nr}. We want to isolate rr.
Multiply both sides by 2nr2nr:
2nmr=rs2nmr = r - s
Rearrange to get all terms with rr on one side:
2nmrr=s2nmr - r = -s
Factor out rr:
r(2nm1)=sr(2nm - 1) = -s
r=s2nm1r = \frac{-s}{2nm - 1}
r=s12nmr = \frac{s}{1 - 2nm}
c) ii)
We are given s=117s=117, m=2m=2, n=3n=-3. Using the rearranged formula:
r=s12nmr = \frac{s}{1 - 2nm}
r=11712(2)(3)r = \frac{117}{1 - 2(2)(-3)}
r=1171(12)r = \frac{117}{1 - (-12)}
r=1171+12r = \frac{117}{1 + 12}
r=11713r = \frac{117}{13}
r=9r = 9

3. Final Answer

a) y=9y = 9
b) 220220 cm
c) i) r=s12nmr = \frac{s}{1-2nm}
ii) r=9r = 9

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