We are given a quadrilateral $SPQR$ with $\angle PSR = 22^\circ$, $\angle SPQ = 58^\circ$, and $\angle PQR = 41^\circ$. We are asked to find the obtuse angle $\angle QRS$.

1. Problem Description

We are given a quadrilateral $SPQR$ with $\angle PSR = 22^\circ$, $\angle SPQ = 58^\circ$, and $\angle PQR = 41^\circ$. We are asked to find the obtuse angle $\angle QRS$.

2. Solution Steps

First, let's find the angle $\angle PSQ$. Since the sum of angles in a triangle is $180^\circ$, we can find $\angle PQS$ in $\triangle PQS$.

$\angle PQS + \angle SPQ + \angle PSQ = 180^\circ$

$\angle PQS + 58^\circ + 22^\circ + \angle RSQ = 180^\circ$

$\angle PQS + \angle RSQ = \angle PQR = 41^\circ$

We know that $\angle SPQ = 58^\circ$, and $\angle PQR = 41^\circ$.

Let $\angle QRS = x$. The sum of the interior angles in a quadrilateral is $360^\circ$.

Thus, $\angle PSR + \angle SPQ + \angle PQR + \angle QRS = 360^\circ$.

$22^\circ + 58^\circ + 41^\circ + x = 360^\circ$

$121^\circ + x = 360^\circ$

$x = 360^\circ - 121^\circ$

$x = 239^\circ$

However, we want the obtuse angle $\angle QRS$, so we calculate $360^\circ - 239^\circ = 121^\circ$.

$\angle QRS$ is the reflex angle, which is $239^\circ$. The other angle is $360^\circ - 239^\circ = 121^\circ$. We want the obtuse angle, so the required angle is $121^\circ$.

3. Final Answer

$121^\circ$

The answer is C.